Home Physics Work, Energy, Power and Collision Work-Energy Theorem A block of mass M is kept on a platform whic…
Physics Work, Energy, Power and Collision Work-Energy Theorem Subjective Type
Published on: September 12, 2026

A block of mass M is kept on a platform which is accelerating upward with a constant acceleration a. During the time interval T,

(i) The word done by gravity is ................

(ii) The work done by normal reaction is .........

(iii) The change in kinetic energy of the block is ..........

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The correct answer is:
A
(i) The work done by gravity is:
The gravitational force acting on the block is $F_g = Mg$, where $g$ is the acceleration due to gravity. Since the platform is accelerating upwards with an acceleration $a$, the effective acceleration acting on the block is $g - a$.
The distance moved by the block in time $T$, under upward acceleration is given by the equation of motion:
$$ d = rac{1}{2}(g - a)T^2 $$
Therefore, the work done by gravity is:
$$ W_g = -F_g imes d = -Mg imes rac{1}{2}(g - a)T^2 = - rac{1}{2}Mg(g - a)T^2 $$
(ii) The work done by the normal reaction is:
The normal force $N$ exerted on the block must balance the weight of the block and provide the upward acceleration:
$$ N = M(g + a) $$
The work done by the normal reaction is given by:
$$ W_N = N imes d = M(g + a) imes rac{1}{2}(g - a)T^2 = rac{1}{2}M(g + a)(g - a)T^2 $$
(iii) The change in kinetic energy of the block is:
The change in kinetic energy $ riangle KE$ is equal to the work done by all forces acting on the block:
$$ riangle KE = W_N + W_g = rac{1}{2}M(g + a)(g - a)T^2 - rac{1}{2}Mg(g - a)T^2 $$
After simplification, using the work-energy principle, we can find the change in kinetic energy concerning the given parameters.

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